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Calculate the e.m.f. of the cell in which the reaction isMg(s) + 2Ag+(aq) → Mg2+(aq) + 2Ag(s)When Mg2+ = 0.130 Mand Ag+ = 1.0 × 10-4M. [Given EMg2+/Mg = -2.37 V and E°Ag+/Ag = 0.80 V]
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Calculate emf of the following cell at 25^∘C . Fe|Fe^2 + (0.001M)|H^+(0.01M)|H2(g)(1 bar)Pt(s)E^∘(Fe^2 + |Fe) = - 0.44 VF^∘(H^+/H2) = 0.00V
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